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What is the net work, in joules, required to stop a bullet of mass 7.73 g that is moving at a speed of 409 m/s
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What is the net work, in joules, required to stop a bullet of mass 7.73 g that is moving at a speed of 409 m/s

User Stigblue
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1 Answer

5 votes

Answer:

KE=1.58J

Step-by-step explanation:

In this problem we are required to solve for the total energy

"The kinetic energy is the energy possessed by a body by virtue of motion"

KE=1/2mv²

Given

Mass m=7.73g

Velocity v=409m/s

In kg= 0.00773kg

KE=1/2*0.00773*409

KE=3.16157/2

KE=1.58J

User Braden
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