90.3k views
5 votes
How many real solutions are in the equation 8-4x=0

User DenVog
by
7.8k points

2 Answers

4 votes
One real solution as they said ^

Examples:
2=2 - infinite solutions
X=2 - one solution ( variable=number)
0=2 - no solutions
User Beanumber
by
7.6k points
4 votes
Answer:
one real solution
Explanation:
8-4x=0
Add 4x to each side
8 = 4x
Divide by 4
8/4 = 4x/4
2 =x
There is one real solution
User Sbac
by
8.3k points

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