How many real solutions are in the equation 8-4x=0

asked Jul 16, 2021 90.3k views

5 votes

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4 votes

One real solution as they said ^

Examples:
2=2 - infinite solutions
X=2 - one solution ( variable=number)
0=2 - no solutions

Beanumber answered Jul 17, 2021

4.5k points

4 votes

Answer:
one real solution
Explanation:
8-4x=0
Add 4x to each side
8 = 4x
Divide by 4
8/4 = 4x/4
2 =x
There is one real solution

Sbac answered Jul 21, 2021

by Sbac

5.0k points

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