Answer: x^2+x-12 = 0 ⇒ x = -4 or x = 3 and x^2-6x+9 = 0 ⇒ x= 3
x^2+x-12 = 0 (Find two numbers that add to 1 and multiply to -12)
x^2-3x+4x-12 = 0 (Factor out like terms)
x(x-3)+4(x-3) = 0 (Group common terms)
(x-3)(x+4) = 0 (Set each term to equal 0 and solve for x)
∴ x = -4 or x = 3
x^2-6x+9 = 0 (It's a perfect square trinomial)
(x-3)^2 = 0
∴ x = 3