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What is the solution set to this equation? log₂ (x - 2) + log₂x = 3​

User Richard Hu
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1 Answer

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Let's see


\\ \rm\Rrightarrow log_2(x-2)+log_2x=3


\\ \rm\Rrightarrow log_2(x(x-2))=3


\\ \rm\Rrightarrow x²-2x=8


\\ \rm\Rrightarrow x(x-2)=8

Either x=8

Or

  • x-2=8
  • x=10

Solution set

x[8,10]

User Mike Brind
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