Question

What is the solution set to this equation? log₂ (x - 2) + log₂x = 3​

Answer 1

Let's see

`\\ \rm\Rrightarrow log_2(x-2)+log_2x=3`

`\\ \rm\Rrightarrow log_2(x(x-2))=3`

`\\ \rm\Rrightarrow x²-2x=8`

`\\ \rm\Rrightarrow x(x-2)=8`

Either x=8

Or

• x-2=8
• x=10

Solution set

x[8,10]