Question

Please help me outttt

Answer 1

(-1, 4) and (2, 7)

Explanation:

• Graphs f(x) & g (x) are intersecting each other.

• -> f(x) = g(x)

• 
  `\implies x^2+3 =x + 5`

• 
  `\implies x^2+3 -x -5=0`

• 
  `\implies x^2 -x -2=0`

• 
  `\implies x^2 -2x +x-2=0`

• 
  `\implies x(x -2) +1(x-2)=0`

• 
  `\implies (x -2)(x+1)=0`

• 
  `\implies (x -2)=0,\:\: (x+1)=0`

• 
  `\implies x=2\:\: x=-1`

• 
  `\implies x=-1,\:\:2`

• When x = -1

• 
  `f(x) = (-1)^2+3 = 1 +3 = 4`

• -> (x, f(x)) = (-1, 4)

• & When x = 2

• 
  `f(x) = (2)^2+3 = 4 +3 = 7`

• -> (x, f(x)) = (2, 7)

• Thus, the points of intersection of the functions f(x) and g(x) are (-1, 4) and (2, 7)