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Write the equation of a line with the slope -3 and y-intercept of 5

O y = 5x + 3
O y = -5x + 3
O y = 5x - 3
O y = -3x + 5

1 Answer

2 votes

Answer:


\fbox{y = -3x + 5}

Explanation:

You are given the slope and the y-intercept of the line; so you can substitute these values into slope-intercept form:
y=mx+b;

  • where
    m= \ $slope = -3
  • and
    y-$int = 5

Plugging these values into slope-intercept form gives:


  • y=(-3)x+(5)

  • y=-3x+5

Another way to find the slope-intercept form of a line given the slope and a point:

We are given the slope and a point that the line passes through, so we can use the point-slope equation to find the slope-intercept form of the line.

The point that the line passes through is the y-intercept:
(0,5).

Point-slope form:


  • y-y_1=m(x-x_1)

where
(x_1, \ y_1) are the coordinates of the point that the line passes through and
m= $ slope of the line.

Substitute
m=-3 and
(0,5) into the point-slope form equation.


  • y-(5)=-3(x-(0))

Simplify the equation on both sides.


  • y-5=-3(x)

Add 5 to both sides of the equation.


  • y=-3x+5

This is in slope-intercept form:
y=mx+b, so we are done.

The answer is
D) \ $y = -3x+5.

User Sekmo
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