Question

Find the value of the expression below. log6 3 + log6 8- log6 4

Answer 1

(C) 1 is the correct answer.

Answer 2

Given:

Consider the expression is

`\log_63+\log_68-\log_64`

To find:

The value of given expression.

Solution:

We have,

`\log_63+\log_68-\log_64`

Using properties of logarithm, we get

`=\log_6(3* 8)-\log_64`
`[\because \log_am+\log_an=\log_amn]`

`=\log_6(24)-\log_64`

`=\log_6\left( (24)/(4)\right)`
`[\because \log_am-\log_an=\log_a(m)/(n)]`

`=\log_66`

`=1`
`[\because \log_aa=1]`

Therefore, the value of given expression is 1.