Answer:
–215 °C
Step-by-step explanation:
From the question given above, the following data were obtained:
Mass of Ne = 10.5 g
Volume (V) = 2.50 L
Pressure (P) = 1 atm
Temperature (T) =?
Next, we shall determine the number of mole present in 10.5 gof Neon, Ne. This can be obtained as follow:
Mass of Ne = 10.5 g
Molar mass of Ne = 20 g/mol
Mole of Ne =.?
Mole = mass /Molar mass
Mole of Ne = 10.5 / 20
Mole of Ne = 0.525 mole
Next, we shall determine the temperature of the sample of Neon, Ne. This can be obtained as follow:
Volume (V) = 2.50 L
Pressure (P) = 1 atm
Number of mole (n) = 0.525 mole
Gas constant (R) = 0.0821 atm.L/Kmol
Temperature (T) =?
PV = nRT
1 × 2.5 = 0.525 × 0.0821 × T
2.5 = 0.525 × 0.0821 × T
Divide both side by 0.525 × 0.0821
T = 2.5 / (0.525 × 0.0821)
T = 58 K
Finally, we shall convert 58 K to degree celsius (°C). This can be obtained as follow:
T(°C) = T(K) – 273
T(K) = 58 K
T(°C) = 58 – 273
T(°C) = –215 °C
Thus, the temperature of the sample of Neon gas is –215 °C.