Question

What is the energy of a photon with a frequency of 2.2 × 1016 Hz? Planck’s constant is 6.63 × 10–34 J•s.

Answer 1

A, 1.5 × 10 ^–17 J

Step-by-step explanation:

edge

Answer 2

First we need to find the wavelength from the frequency using
`C = \lambda V`

so
`3.0e8 = \lambda * 2.2e16 Hz` which equals 1.36e-8 m then we use the formula
`E =h (C)/(\lambda)` we plug in
`E = 6.63e-34 * (3.0e8/1.36e-8)` and we get
`E = 1.46e-17`

so the energy is 1.46 x 10^-17 J.