Question

within a balloon there are 3 types of gases. the first gas, A, is 6.0 grams in amount, the second gas, B, is 4.0 grams and the last, C, is 3.5 grams. The molar mass of gas "A" is 13.56 g/mol, "B" is 11.76 g/mol and "C" is 12.07 g/mol. If the total pressure inside the balloon is 15 atm, what is the partial pressure of each gas?

Answer 1

Partial pressure of Gas A = 3.91 atm

Partial pressure of Gas B = 5.10 atm

Partial pressure of Gas C = 5.99 atm

Step-by-step explanation:

Number of moles of gas A;

n_A = 13.56 g/mol ÷ 6 g = 2.25 moles

Number of moles of gas B;

n_B = 11.76 g/mol ÷ 4 g

n_B = 2.94 moles

Number of moles of gas C;

n_C = 12.07 g/mole ÷ 3.5 moles

n_C = 3.45 moles

Total number of moles = n_A + n_B + n_C = 2.25 + 2.94 + 3.45 = 8.64 moles

Mole fraction of gas A; X_a = 2.25/8.64

Mole fraction of gas B;X_b = 2.94/8.64

Mole fraction of gas C;X_c = 3.45/8.64

Now, partial pressure of each gas will be;

Mole fraction × Total pressure

We are given total pressure of 15 atm.

Thus;

P_a = (2.25/8.64) × 15

P_a = 3.91 atm

P_b = (2.94/8.64) × 15

P_b = 5.10 atm

P_c = (3.45/8.64) × 15

P_c = 5.99 atm

Thus;

Partial pressure of Gas A = 3.91 atm

Partial pressure of Gas B = 5.10 atm

Partial pressure of Gas C = 5.99 atm