4.1k views
11 votes
Which of the following is a solution to 2sin^2x+sinx-1=0?

A. 45 degrees
B. 200 degrees
C. 240 degrees
D. 270 degrees
E. 330 degrees

User Phoenixo
by
7.0k points

2 Answers

8 votes

Answer


x = (\pi )/(6) + 2\pi n, (5\pi )/(6) + 2\pi n, (3\pi )/(2) + 2\pi n, for any integer n

User Henrik R
by
8.2k points
7 votes

Answer:

D or 270°

Explanation:

2sin^2x+sinx-1

2sin^2(270°)+sin(270°)-1=0

User Tec
by
7.6k points

Related questions

asked Jun 25, 2024 74.0k views
Chris Mansley asked Jun 25, 2024
by Chris Mansley
7.7k points
1 answer
0 votes
74.0k views
asked May 10, 2017 194k views
Ed Bayiates asked May 10, 2017
by Ed Bayiates
8.7k points
2 answers
2 votes
194k views