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11 votes
Which of the following is a solution to 2sin^2x+sinx-1=0?

A. 45 degrees
B. 200 degrees
C. 240 degrees
D. 270 degrees
E. 330 degrees

User Phoenixo
by
3.5k points

2 Answers

8 votes

Answer


x = (\pi )/(6) + 2\pi n, (5\pi )/(6) + 2\pi n, (3\pi )/(2) + 2\pi n, for any integer n

User Henrik R
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4.4k points
7 votes

Answer:

D or 270°

Explanation:

2sin^2x+sinx-1

2sin^2(270°)+sin(270°)-1=0

User Tec
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4.0k points