Question

What will be the volumetric flow through the pipe if the mean fluid velocity is 10 ft/sec and the pipe has an outer diameter of 4.95 inches and a thickness of 0.25 inch

Answer 1

The volumetric flow through the pipe is 1.21 ft³/s

Step-by-step explanation:

Given;

fluid mean velocity, v = 10 ft/s

outer diameter of the pipe, d₀ = 4.95 inches = 0.4125 ft

thickness of the pipe, x = 0.25 inches = 0.0208 ft

the inner diameter of the pipe, d₁ = d₀ - x = 0.4125 ft - 0.0208 ft = 0.3917 ft

the area of the pipe =
`A = (\pi d_i^2)/(4) = (\pi * 0.3917^2)/(4) = 0.121 \ ft^2`

The volumetric flow rate of the pipe is given by;

Q = Av

Q = (0.121 ft²) (10 ft/s)

Q = 1.21 ft³/s

Therefore, the volumetric flow through the pipe is 1.21 ft³/s