Question

The steel and concrete in the left column are bonded so that there is no slip. What is the deformation in this column due to the applied load

Answer 1

hello your question is incomplete attached below is the missing part of the question

Answer : ≈ 0.0284 mm

Step-by-step explanation:

The deformation in the left column can be calculated using this relationship

Deformation ( δ ) =
`(F_(1) * h)/(A_(c)E_(c) + A_(s)E_(s) )` --------- ( 1 )

Given :

Es = 200 GPa

Ec = 30 GPa

F1 = 41.9 KN ( as calculated )

`A_(c) = (\pi )/(4) * ( d_(c) ^2 - d_(s) ^2 )` = 298.45
`cm^2`

also

`A_(s) = (\pi )/(4) * d_(s) ^2` = 153.94
`cm^2`

insert the given values into equation 1 above

Deformation ( δ ) = 2.84 * 10^-5 m ≈ 0.0284 mm