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Lithium metal will react with aqueous aluminum sulfate. Write and balance the equation for this rxn, and then determine how many g of aluminum will result from 68.6 g lithium reacting with aluminum sulfate in excess.

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Answer:

88.2 gram of aluminium .

Step-by-step explanation:

6Li + Al₂ ( SO₄)₃ = 3Li₂SO₄ + 2Al

6 x 7 g 2 x 27 g

42 gram of lithium produces 54 gram of aluminium

68.6 gram of lithium will produce 88.2 gram of aluminium .

88.2 gram of aluminium will be produced.

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