9.5k views
0 votes
5. Determine the maximum number of real zeros.f
(x)=(x-1/3)^2(x-1)^3

User KoCMoHaBTa
by
8.3k points

1 Answer

3 votes

Answer:

The maximum number of real zeros of the function is 5.

Explanation:

Zeros of a polynomial

Any polynomial of positive order can have a maximum number of zeros equal to its order. For example, a quadratic function can have as many as two zeros.

The given polynomial is:


f(x)=(x-1/3)^2(x-1)^3

The order of this polynomial is 5 since it's factored as a quadratic polynomial by a cubic polynomial. The order is 2+3=5.

Thus, the maximum number of real zeros of the function is 5.

User Ashfaq
by
7.8k points

No related questions found

Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.