Segment BH bisects angle ABC, the angle ABH =7x-5 and the angle CBH =3x+11. Find the angle of ABC

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asked Mar 1, 2021 205k views

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Segment BH bisects angle ABC, the angle ABH =7x-5 and the angle CBH =3x+11. Find the angle of ABC

Segment BH bisects angle ABC, the angle ABH =7x-5 and the angle CBH =3x+11. Find the-example-1

Mathematics
high-school

Andrew Leap asked

by Andrew Leap

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Answer:

$angle \: abc = 46. \\ angle \: bac = 67. \\ angle \: acb = 67. \\$

Explanation:

$angle \: ABH \: =7x - 5 \\ and \\ angle \: CBH =3x+11. \\ but \: ABH = CBH \\ so \: 7x - 5 = 3x + 11 \\ 4x = 16 \\ x = 4. \\ then \\7x - 5 = 23. \\ 3x+11 = 23.$

RedX answered Mar 4, 2021

by RedX

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