80.8k views
4 votes
I need help asap please

I need help asap please-example-1

1 Answer

2 votes

Answer:

  • 52 seconds
  • 5833 feet

Explanation:

Each plane has a starting altitude and a fixed rate of climb. Its altitude at some time t will be the sum of the starting altitude and t times the rate of climb.

__

plane A

altitude = starting altitude + t × rate of climb

a(t) = 4000 +35.25t

plane B

b(t) = 2427 +65.5t

same altitude

The planes will be at the same altitude at the same time when ...

a(t) = b(t)

4000 +35.25t = 2427 +65.5t

1573 = 30.25t . . . . . . . . . . subtract 2427+35.25t

52 = t . . . . . . . . . . . . . divide by 30.25

That altitude is ...

a(52) = 4000 +35.25×52 = 4000 +1833 = 5833

summary

52 seconds will pass before the planes are at the same altitude.

Their altitude then will be 5833 feet.

I need help asap please-example-1
User Miwako
by
7.8k points

No related questions found

Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

9.4m questions

12.2m answers

Categories