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Solve A=½h(b₁+b₂) for b₁
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Solve A=½h(b₁+b₂) for b₁

User Sanvir Manilal
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Answer:

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Explanation:


A = (1)/(2) h(b_1+b₂) \\ \\ 2A = h(b_1+b₂) \\ \\ (2A)/(h) = b_1+b₂ \\ \\ (2A)/(h) -b₂ = b_1 \\ \\ (2A -b₂ h )/(h) = b_1 \\ \\ \huge \red{ \boxed{b_1 = (2A -b₂ h )/(h) }}

User Abelito
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