Question

On a coordinate plane, a curved line with a minimum value of (5.1, negative 7) and a maximum value of (0, 25), crosses the x-axis at (negative 3.4, 0), (3.9, 0), and (6, 0), and crosses the y-axis at (0, 25).

Which statement is true about the local minimum of the graphed function?

Over the interval [–4, –2], the local minimum is 0.
Over the interval [–2, –1], the local minimum is 25.
Over the interval [–1, 4], the local minimum is 0.
Over the interval [4, 7], the local minimum is -7.

Answer 1

The answer would be D

Explanation:

Answer 2

D

Explanation:

The rest of the question is the attached figure and the statement options.

A. Over the interval [–4, –2], the local minimum is 0.

B. Over the interval [–2, –1], the local minimum is 25.

C. Over the interval [–1, 4], the local minimum is 0.

D. Over the interval [4, 7], the local minimum is -7.

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According to the graph, we will check the options:

A. Over the interval [–4, –2], the local minimum is 0. (Wrong)

Because the minimum is -12

B. Over the interval [–2, –1], the local minimum is 25. (Wrong)

Because the minimum is 18

C. Over the interval [–1, 4], the local minimum is 0. (Wrong)

Because the minimum is at x = 4 less than zero

D. Over the interval [4, 7], the local minimum is -7. (True)