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Find two consecutive odd numbers such that seven times the smaller number is 17 more than six times the larger

User MacroMan
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1 Answer

4 votes

Answer:

29 and 31

Explanation:

Let

x = the first odd number

x + 2 = the second odd number

seven times the smaller number is 17 more than six times the larger

7*x = 17 + 6(x + 2)

7x = 17 + 6x + 12

Collect like terms

7x - 6x = 29

x = 29

x + 2 = 29 + 2

= 31

Check:

7*x = 17 + 6(x + 2)

7*29 = 17 + 6(29 + 2)

203 = 17 + 6(31)

203 = 17 + 186

203 = 203

Therefore, the two consecutive odd numbers are 29 and 31

User Jayabalaji J
by
4.5k points