Question

What is the solution for (x+2)²+5=0

Answer 1

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We know that the square of any number is greater or equal to zero Thus ;

`({x + 2})^(2) \geqslant 0`

And ;

`5 > 0`

Sum of the two positive numbers never equal zero Thus there isn't any value for x

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Answer 2

Explanation:

(x+2)²+5=0

`x^(2) +4+5 = 0`

`x^(2) +9 = 0`

`x^(2) = -9`

x= no solution