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I chose x=3 , x=-4 which was wrong the correct answer is x=1 , x=-2

can someone please explain how to get that answer

I chose x=3 , x=-4 which was wrong the correct answer is x=1 , x=-2 can someone please-example-1

2 Answers

1 vote

Answer:

vertical asymptotes is x = -2 and x = 1

Explanation:

For rational functions, the vertical asymptotes are the undefined points, also known as the zeros of the denominator (below the line), of the simplified function.

This means
-4x^(2) - 4x + 8 is equal to zero than solve

*image below*

Hope it helps :)

Let me know if you have any questions or anymore help lmk, happy to help with any school work!!

I chose x=3 , x=-4 which was wrong the correct answer is x=1 , x=-2 can someone please-example-1
User Jeremythuff
by
8.6k points
10 votes

We are give with the function:


{\quad \qquad \longrightarrow f(x)=(x^(2)+x-12)/(-4x^(2)-4x+8)}

Vertical asymptotes are the points, where the function is not defined, so the denominator must be equal to 0 for making f(x) not defined


{:\implies \quad \sf -4x^(2)-4x+8=0}

Dividing both sides by -4, we have;


{:\implies \quad \sf x^(2)+x-2=0}

Can be further written as:


{:\implies \quad \sf x^(2)-x+2x-2=0}


{:\implies \quad \sf x(x-1)+2(x-1)=0}


{:\implies \quad \sf (x-1)(x+2)=0}

Using zero product rule, Equating both multiplicants to 0, we have:


{:\implies \quad \boxed{\bf{x=1\quad or\quad -2}}}

This is the required answer

User Desiigner
by
7.9k points

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