Tell how many solutions each equation would have: one solution, no solutions, or infinitely many solutions. Give a justification for your answer. 6x-5=2(3x+4)

My account
Edit my Profile
Private messages
My favorites

Ask a Question
Questions
Unanswered
Tags
Categories
Ask a Question

asked Jun 15, 2021 33.6k views

0 votes

Tell how many solutions each equation would have: one solution, no solutions, or infinitely many solutions. Give a justification for your answer.

6x-5=2(3x+4)

Mathematics
high-school

JARC asked

by JARC

5.1k points

0 Comments

Please log in or register to add a comment.

Please log in or register to answer this question.

2 Answers

1 vote

Answer:

Explanation:

6x-5=6x+8

allready it is a no solution

Comzyh answered Jun 15, 2021

by Comzyh

5.4k points

0 Comments

Please log in or register to add a comment.

0 votes

Answer:

No solution

Explanation:

There is no number you can put in for x to make this equation true

Christophe Lallement answered Jun 21, 2021

by Christophe Lallement

5.9k points

0 Comments

Please log in or register to add a comment.

Ask a Question

Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

5.9m questions

7.8m answers

0 Comments

Please log in or register to add a comment.

Please log in or register to answer this question.

2 Answers

0 Comments

Please log in or register to add a comment.

0 Comments

Please log in or register to add a comment.

Other Questions