Answer:lim x- √16-x²=32
Explanation:
-16
=(x²)²-4²
=(x²-4)(x²+4)
=(x²-2²)(x²+4)
=(x-2)(x+2)(x²+4)
So:
==(x+2)(+4)
with exclusion:
x2
Hence:
lim
x-2
((x+2)(+4))=
((2)+2)((2)²+4)=4⋅8=32
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