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Which numbers complete the blanks when solving the equation cos(x+2pi)= -(square root of 2/2) over the interval [0, 2pi]?

Which numbers complete the blanks when solving the equation cos(x+2pi)= -(square root-example-1
User Kkirsche
by
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2 Answers

4 votes

Answer:

A 1;0

Explanation:

User Celeste
by
4.1k points
4 votes

Answer:

1, 0

Explanation:

Let
\cos (x+2\pi) = -(√(2))/(2). From Trigonometry we remember the following identity:


\cos (a+b) = \cos a \cdot \cos b - \sin a \cdot \sin b (Eq. 1)

Where
a and
b are angles measured in radians.

Then, we proceed to expand the given expression:


\cos x \cdot \cos 2\pi - \sin x \cdot \sin 2\pi = -(√(2))/(2)


\cos x \cdot 1 - \sin x \cdot 0 = -(√(2))/(2)


\cos x = -(√(2))/(2)

Therefore, correct answer is "1, 0".

User Jerson
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3.9k points