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Find the mass of Iron (III) nitrate that is dissolved by water to make 500mL and 0.2M of solution iron (III) nitrate. (Fe =56, N =14, O =16)

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0.2M = 0.2mol/1L
0.2mol/L • 0.5L = 0.1mol
Fe(NO3)3 = 242g/mol
242g/mol • 0.1mol = 24.2g is the dissolved mass
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