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A little help with all of them hehe​

A little help with all of them hehe​-example-1
User Shahab Saalami
by
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1 Answer

14 votes
14 votes

Answer:

  1. 280 torr
  2. 2.53 L
  3. 192884.8 Pa
  4. 11.46 moles

Step-by-step explanation:

Q1

According to The Ideal Gas Equation :

  • P₁V₁/T₁ = P₂V₂/T₂
  • P₁V₁ = P₂V₂ (as T₁ = T₂)
  • P₂ = P₁V₁/V₂
  • P₂ = 560 x 145 / 290
  • P₂ = 560 x 0.5
  • P₂ = 280 torr

Q2

  • P₁V₁/T₁ = P₂V₂/T₂
  • V₁/T₁ = V₂/T₂
  • V₂ = V₁T₂/T₁
  • V₂ = 3 x (273 - 20) / (273 + 27)
  • V₂ = 3 x 253 / 300
  • V₂ = 253 x 0.01
  • V₂ = 2.53 L

Q3

  • PV = nRT
  • P = nRT/V
  • P = 0.4 x 8.314 x (17 + 273) / 5 x 10⁻³
  • P = 0.4 x 8.314 x 290 x 10³ / 5
  • P = 400 x 8.314 x 58
  • P = 23200 x 8.314
  • P = 192884.8 Pa

Q4

  • PV = nRT
  • n = PV/RT
  • n = 2.8 x 98 / 0.082 x 292
  • n = 274.4/23.944
  • n = 11.46 moles
User Htz
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