Answer:
- 280 torr
- 2.53 L
- 192884.8 Pa
- 11.46 moles
Step-by-step explanation:
Q1
According to The Ideal Gas Equation :
- P₁V₁/T₁ = P₂V₂/T₂
- P₁V₁ = P₂V₂ (as T₁ = T₂)
- P₂ = P₁V₁/V₂
- P₂ = 560 x 145 / 290
- P₂ = 560 x 0.5
- P₂ = 280 torr
Q2
- P₁V₁/T₁ = P₂V₂/T₂
- V₁/T₁ = V₂/T₂
- V₂ = V₁T₂/T₁
- V₂ = 3 x (273 - 20) / (273 + 27)
- V₂ = 3 x 253 / 300
- V₂ = 253 x 0.01
- V₂ = 2.53 L
Q3
- PV = nRT
- P = nRT/V
- P = 0.4 x 8.314 x (17 + 273) / 5 x 10⁻³
- P = 0.4 x 8.314 x 290 x 10³ / 5
- P = 400 x 8.314 x 58
- P = 23200 x 8.314
- P = 192884.8 Pa
Q4
- PV = nRT
- n = PV/RT
- n = 2.8 x 98 / 0.082 x 292
- n = 274.4/23.944
- n = 11.46 moles