Answer:
0.1M
Step-by-step explanation:
So, we are given the following data or parameters which is going to help in solving this particular Question:
=> There are two compounds/elements compound/element X and compound/element Y.
(NB: We are not giving the atomicity)
=> "A 50.0 mL volume of 0.50 M of X is mixed with 50.0 mL of 0.20 M of Y."
Thus, X + Y ---------------------------> XY(aq).
The first thing to do here is to determine the number of moles of each reactants that is X and Y.
The number of moles of X = 0.50M × 50 × 10^-3 L = 0.025 moles.
The number of moles of Y = 0.20M × 50 × 10^-3 L = 0.01 moles.
Hence, we have that 0.025 moles of X reacted with 0.01 moles of Y to give XY.
The limiting reagent/reactant is Y.
Therefore, 0.01 mole of Y × (1 mole XY/1 mole of Y) = 0.01 moles of XY.
Thus, the number of moles of XY is 0.01 mole.
Hence, we have that 0.025 moles of X reacted with 0.01 moles of Y to give 0.01 moles of XY.
So, the molarity or the concentration of XY(aq) = 0.01/(100 × 10^-3 ) = 0.1M