Question

How many moles of argon atoms are present in 11.2 L of argon gas at STP?​

Answer 1

Using the older standard, as indicated in the explanation, 11.2 L of Ar atoms contain 0.500 mol

Step-by-step explanation:

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Answer 2

Answer: 0.493 mol Ar or 0.500 mol Ar (ROUNDED)

Explanation: Simplify by multiplying by the inverse of the molar volume.

11.2L × 1 mol / 22.710 L = 0.493 mol Ar

Using the older STP values of 0∘C or 273.15 K, and pressure of 1 atm

, molar volume is 22.414 L/mol.

11.2 L × 1 mol / 22.414 L = 0.500 mol Ar