Question

A car travels at a constant speed around a circular track whose radius is 3.22 km. The car goes once around the track in 248 s. What is the magnitude of the centripetal acceleration of the car

Answer 1

a = 1,838.17m/s²

Step-by-step explanation:

centripetal acceleration a = v²/r

v is velocity of the car

r is the radius = 3.22km = 3220m

time t = 248

First is to find to velocity using the equation of motion:

v = u+gt

v = 0+(9.81)(248)

v = 2,432.88m/s

a = 2,432.88²/3220

a = 5,918,905.0944/3220

a = 1,838.17m/s²

The magnitude of the centripetal acceleration of the car is 1,838.17m/s²