The options are missing from the question,
Below are the options.
A) Tag would be CO2
B) Acetate in C-2
C) 1 uvate in C-3
D) pyruvate in C-3
E) oxaloacetate on C-1
F) palmitate in C-16
The correct answer to the question is option B
ACETATE IN C-2
If palmitate (16:0) which is a fatty acid radiolabeled with 14C in C-16, when metabolized under anaerobic conditions by mammalian cells,the compound that will be tagged with 14C will be ACETATE and the position it will be will be C-2
In an anaerobic condition, anaerobic CoA which is formed after the oxidation of fatty acid will now move into the Kreb cycle as a result of oxygen deficiency, taking the form of acetate,it will enter cytosol and will further be used for other purposes.