Question

The mean hourly wage for employees in goods-producing industries is currently $24.57 (Bureau of Labor Statistics website, April, 12, 2012). Suppose we take a sample of employees from the manufacturing industry to see if the mean hourly wage differs from the reported mean of $24.57 for the goods-producing industries. a. State the null hypotheses we should use to test whether the population mean hourly wage in the manufacturing industry differs from the population mean hourly wage in the goods-producing industries. 1. 2. 3. Choose correct answer from above choice 1 State the alternative hypotheses we should use to test whether the population mean hourly wage in the manufacturing industry differs from the population mean hourly wage in the goods-producing industries. 1. 2. 3. Choose correct answer from above choice 1 b. Suppose a sample of 30 employees from the manufacturing industry showed a sample mean of $23.89 per hour. Assume a population standard deviation of $2.40 per hour and compute the p-value. Round your answer to four decimal places. .9588 c. With

Answer 1

Kindly check explanation

Explanation:

Given that:

Population Mean wage (m) = $24.57

a. State the null hypotheses we should use to test whether the population mean hourly wage in the manufacturing industry differs from the population mean hourly wage in the goods-producing industries.

The Null hypothesis : μ = 24.57

1 State the alternative hypotheses we should use to test whether the population mean hourly wage in the manufacturing industry differs from the population mean hourly wage in the goods-producing industries.

Alternative hypothesis : μ ≠ 24.57

1 b. Suppose a sample of 30 employees from the manufacturing industry showed a sample mean of $23.89 per hour. Assume a population standard deviation of $2.40 per hour and compute the p-value.

Sample size (n) = 30

Sample mean (Sm) = 23.89

Population standard deviation (σ) = 2.40

Obtaining Z:

Z = (Sm - m) / σ/√n

Z = (23.89 - 24.57) / 2.40/√30

Z = - 0.68 / 0.4381780

Z = - 1.5518805

Using the online p value calculator from Zscore

P value = 0.121142

= 0.1211