Question

A wheelchair ramp is being built with a slope of 3/28. What angle will the ramp make with the horizontal?

Answer 1

Check the picture below.

`tan(\theta )=\cfrac{\stackrel{opposite}{3}}{\underset{adjacent}{28}}\implies tan^(-1)[tan(\theta )]=tan^(-1)\left( \cfrac{3}{28} \right) \\\\\\ \theta =tan^(-1)\left( \cfrac{3}{28} \right)\implies \theta \approx 6.12^o`

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