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A wheelchair ramp is being built with a slope of 3/28. What angle will the ramp make with the horizontal?

User Dxiv
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Check the picture below.


tan(\theta )=\cfrac{\stackrel{opposite}{3}}{\underset{adjacent}{28}}\implies tan^(-1)[tan(\theta )]=tan^(-1)\left( \cfrac{3}{28} \right) \\\\\\ \theta =tan^(-1)\left( \cfrac{3}{28} \right)\implies \theta \approx 6.12^o

Make sure your calculator is in Degree mode.

A wheelchair ramp is being built with a slope of 3/28. What angle will the ramp make-example-1
User Staticx
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