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Find the non-extraneous solutions of squareroot of x+6-5=x+1 X=-2 X=-6 and x = -5 X= -6 and x = -2 X=2
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May 6, 2021
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Find the non-extraneous solutions of squareroot of x+6-5=x+1
X=-2
X=-6 and x = -5
X= -6 and x = -2
X=2
Mathematics
high-school
DrewJordan
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Answer:
the answer is: X=2
Tink
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May 13, 2021
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