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Find the non-extraneous solutions of squareroot of x+6-5=x+1 X=-2 X=-6 and x = -5 X= -6 and x = -2 X=2

Find the non-extraneous solutions of squareroot of x+6-5=x+1 X=-2 X=-6 and x = -5 X= -6 and x = -2 X=2
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Find the non-extraneous solutions of squareroot of x+6-5=x+1

X=-2
X=-6 and x = -5
X= -6 and x = -2
X=2

User DrewJordan
by
7.8k points

1 Answer

5 votes

Answer:

the answer is: X=2

User Tink
by
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