A toroidal solenoid has an inner radius of 12.0 cm and an outer radius of 15.0 cm . It carries a current of 1.50 A . Part A How many equally spaced turns must it have so that it …

Question

asked Mar 7, 2021 142k views

1 Answer

Rodrigo Taboada · Answer 1 · 2021-03-13T08:47:27+0000

Answer:

The number of turns is
$N  = 1750 \ turns$

Step-by-step explanation:

From the question we are told that

The inner radius is
$r_i =  12.0 \  cm  =  0.12 \  m$

The outer radius is
$r_o =  15.0 \  cm  =  0.15 \  m$

The current it carries is
$I =  1.50 \  A$

The magnetic field is
$B  =   3.75 mT = 3.75 *10^(-3) \  T$

The distance from the center is
$d =  14.0 \ cm  =  0.14 \  m$

Generally the number of turns is mathematically represented as

$N  =  (2 *  \pi  * d  *  B)/( \mu_o *  r_o )$

Generally
$\mu_o$ is the permeability of free space with value

$\mu_o  =  4\pi * 10^(-7) \ N/A^2$

So

$N  =  (2 *  3.142   * 0.14 *  3.75 *10^(-3) )/( 4\pi * 10^(-7)  * 0.15  )$

$N  = 1750 \ turns$