A ball is thrown with an initial velocity of 32 ft/s from a height of 4.5 feet. It’s height as a function of time is given by the equation h(t)=-16t2+32t+4.5. How long will the ball be in the air, and

asked Feb 17, 2021 139k views

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Answer:

the ball will be in the air for possibly 2.5 seconds and it max hieght was 10 ft

Explanation:

no clue

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