Question

a tiger leaps with an initial velocity of 55 km/hr at an angle of 13° with respect to the horizontal. what are the components of the tigers velocity?

Answer 1

vₓ = 53.6 km/h

vy = 12.4 km/h

Step-by-step explanation:

• if we define two axis perpendicular each other with origin in the point represented by the tiger leaping (assuming we can treat it as a point mass) coincidently with the horizontal (x-axis) and vertical (y-axis) directions, we can obtain the components of the velocity in both independent directions.
• We can do it simply getting the projections of the velocity vector on both axes, using simple trigonometry, as follows:

`v_(x) = v_(o) * cos \theta = 55 km/h * cos 13 = 53.6 km/h`

`v_(y) = v_(o) * sin\theta = 55 km/h * sin 13 = 12.4 km/h`