Question

PLEASE HELP ASAP

A physics student is adjusting the settings of their projectile launcher. If the VX =28 m/s and the Vy = 15 m/s, what is the magnitude of its velocity?32 m/s
13 m/s
43 m/s
1009 m/s

Answer 1

The first choice (32m/s) is the closest to the answer

Step-by-step explanation:

The magnitude of a vector is the distance between the initial and the end point of the vector.

Being Vx and Vy the horizontal and vertical components of the vector V respectively, the magnitude of V is calculated as:

`\mid \vec{V} \mid =√(V_x^2+V_y^2)`

The components of the velocity of the physics student's projectile launcher are Vx=28 m/s and Vy=15 m/s.

Calculate the magnitude of the velocity:

`\mid \vec{V} \mid =√(28^2+15^2)`

`\mid \vec{V} \mid =√(784+225)`

`\mid \vec{V} \mid =√(1009)`

`\mid \vec{V} \mid =31.8 \ m/s`

The first choice (32m/s) is the closest to the answer