Question

A red rubber ball rolls down a hill from rest with an acceleration of 7.8 m/s 2 . How fast is it moving after it has traveled 5 m?

Answer 1

8.83m

Step-by-step explanation:

Given parameters:

Acceleration = 7.8m/s²

Initial velocity = 0m/s

distance covered = 5m

Unknown:

Final velocity = ?

Solution:

The equation to solve this problem with is given as;

V² = U² + 2aS

V is the final velocity

U is the initial velocity

a is the acceleration

S is the distance

Input the parameters and solve;

V² = 0² + 2 x 7.8 x 5 = 78

V = √78 = 8.83m