Question

A container of gas has a volume of 280 mL at a temperature of 22 Celsius if the pressure remains constant what is the volume 44 Celsius?

Answer 1

300.9mL

Step-by-step explanation:

Given parameters:

V₁ = 280mL

T₁ = 22°C

T₂ = 44°C

Unknown:

V₂ = ?

Solution:

To solve this problem, we apply Charles's law;

it is mathematically expressed as;

`(V_(1) )/(T_(1) ) = (V_(2) )/(T_(2) )`

We need to convert the temperature to kelvin;

T₁ = 22°C = 22 + 273 = 295K

T₂ = 44°C = 44 + 273 = 317K

Input the parameters and solve;

`(280)/(295)` =
`(V_(2) )/(317)`

V₂ x 295 = 280 x 317

V₂ = 300.9mL