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Four different towns in the same state grew in size due to a revitalization effort. The population of town A grew from 22,000 to 24,500 in 4 years. The population of town B grew from 31,200 to 34,770 in 6 years. The population of town C grew from 18,000 to 22,000 in 5 years. The population of town D grew from 32,000 to 34,100 in 3 years. Which town had the greatest average change in population over the corresponding time period?(1 point)

User Shawn Lu
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1 Answer

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Answer:

Town C.

Explanation:

Average change of population with time for town A =
(24,500 - 22,000)/(4) = (2,500)/(4) = 625

Average change of population with time for town B =
(34,770 - 31,200)/(6) = (3,570)/(6) = 595

Average change of population with time for town C =
(22,000 - 18,000)/(5) = (4,000)/(5) = 800

Average change of population with time for town D =
(34,100 - 32,000)/(3) = (2,100)/(3) = 700

Town C had the greatest average change in population over time (800/yr).

User Jiahut
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