Question

When 28.0 g of acetylene reacts with hydrogen, 24.5 g of ethane is produced. What is the percent yield of C2H6 for the reaction?

C2H2(g) + 2H2(g) → C2H6(g)

Answer 1

`Y=75.6\%`

Step-by-step explanation:

Hello.

In this case, since no information about the reacting hydrogen is given, we can assume that it completely react with the 28.0 g of acetylene to yield ethane. In such a way, via the 1:1 mole ratio between acetylene (molar mass = 26 g/mol) and ethane (molar mass = 30 g/mol), we compute the yielded grams, or the theoretical yield of ethane as shown below:

`m_(C_2H_6)^(theoretical)=28.0gC_2H_2*(1molC_2H_2)/(26gC_2H_2)*(1molC_2H_6)/(1molC_2H_2) *(30gC_2H_6)/(1molC_2H_6)\\ \\m_(C_2H_6)^(theoretical)=32.3gC_2H_6`

Hence, by knowing that the percent yield is computed via the actual yield (24.5 g) over the theoretical yield, we obtain:

`Y=(24.5g)/(32.3g)*100\%\\ \\Y=75.6\%`

Best regards.