Question

What is the specific heat of a metal if the temperature of a 12.5 g sample increases from 19.5 C to 33.6 C when it absorbs 37.7 J of heat.

Answer 1

0.213 J/g°C

Step-by-step explanation:

To calculate specific heat of the metal, the formula is used:

Q = m × c × ∆T

Where Q = amount of heat

m = mass

c = specific heat

∆T = change in temperature

According to this question, Q = 37.7 J, m= 12.5 g, initial temperature= 19.5 °C, final temperature = 33.6°C, c=?

Q = m × c × ∆T

37.7 = 12.5 × c × (33.6-19.5)

37.7 = 12.5c × 14.1

37.7 = 176.25c

c = 37.7/176.25

c = 0.2139

Hence, the specific heat of the metal is 0.213 J/g°C