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Proportions please help! ​

Proportions please help! ​-example-1
User Kashlo
by
6.3k points

2 Answers

3 votes

Answer:


x= -12

Explanation:

Step 1: Write equation


(5)/(x-3) =(7)/(x-9)

Step 2: Solve for x

  1. Cross multiply:
    5(x-9)=7(x-3)
  2. Distribute:
    5x-45=7x-21
  3. Subtract 5x on both sides:
    -45=2x-21
  4. Add 21 to both sides:
    -24=2x
  5. Divide both sides by 2:
    -12=x
  6. Rewrite:
    x= -12

Step 3: Check

Plug in x to verify it's a solution.


(5)/(-12-3) =(7)/(-12-9)


(5)/(-15) =(7)/(-21)


(-1)/(3) =(-1)/(3)

User Gagan Gami
by
6.9k points
4 votes

Answer:


\huge\boxed{x=-12}

Explanation:

In order to solve for this proportion, it’s important to note that this is basically just an equation. Like any other, our goal is to isolate x on one side.

Since we have two fractions, we can multiply both sides by both the denominators (x-3 and x-9). Since one will cancel out the other, we can just multiply both sides by the opposite denominator.


5(x-9)=7(x-3)\\\\5x-45=7x-21

Now we can solve for x.

Subtract 5x from both sides:


-45=2x-21

Add 21 to both sides:


-24=2x

Divide both sides by 2:


x = -12

Hope this helped!

User Kroky
by
6.4k points
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