Question

Calculate the heat that must be supplied to

a 532 , stainless steel vessel containing 375 g
of water to raise its temperature from 35 C
to the boiling point of water 100°C. Cs. =0.51 J/g. degrees C
Answer in units of J.

Answer 1

Q must be supplied = 119523.3~J

Further explanation

The law of conservation of energy can be applied to heat changes, i.e. the heat received/absorbed is the same as the heat released

Q in = Q out

Heat can be calculated using the formula:

Q = mc∆T

Q = heat, J

m = mass, g

c = specific heat, joules / g ° C

∆T = temperature difference, ° C / K

So from the question :

Q to the system(Q supplied) = Q water + Q steel vessel(Q gained)

`\tt Q~supplied=m.c\Delta T(water)+m.c\Delta T(vessel)\\\\Q~supplied=375* 4.18* (100-35)+532* 0.51(100-35)\\\\Q~supplied=101887.5+17635.8=119523.3~J`