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15 percent input work is lost due to friction,then what is the efficiency of machine?​

1 Answer

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Answer:

{ (x/y )*100 } - 0.15 y

Step-by-step explanation:

The efficiency of a machine is the percent of output work divided by input work minus work lost from friction and heat.

Assume work output = x

Assume work input percent as =y

Work lost through friction is given as : 15% input work = 0.15 y

Then efficiency of the machine will be :{ (x/y )*100 }- 0.15 y

Use real values for x and y to find the correct efficiency of the machine.

User Nkassis
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